What is the heat added to this monatomic ideal gas

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To determine the heat added to a monatomic ideal gas expanding at a constant pressure of 110 kPa from 0.75 m³ to 0.93 m³, the work done on the gas can be calculated using W = P∆V. The change in internal energy, ∆U, can be expressed as ∆U = (3/2)nR∆T, where n is the number of moles and R is the ideal gas constant. The heat added, Q, is then found using the equation Q = ∆U + W. The discussion highlights the need for assumptions regarding temperature change to accurately calculate ∆U. Understanding these relationships is crucial for solving the problem effectively.
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Homework Statement


A monatomic ideal gas expands at a pressure of 110kPa and from a volume of 0.75m^3 to 0.93m^3. Find the amount of heat added to the gas.


Homework Equations


So what I did was:
W= P∆V
and I know ∆U= Q-W
so Q would equal ∆U+W, but how do you know what ∆U equals?


The Attempt at a Solution

 
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what are you assumptions? that will tell you what delta U is equal to.
 


If I assume that this is at a constant pressure ∆U= 3/2nR∆T?, but since W=P∆V=nR∆T then ∆U= 3/2W?
 
Thread 'Correct statement about size of wire to produce larger extension'

Thread 'Correct statement about size of wire to produce larger extension'

The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...
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