What is the Induced EMF and Current in a Changing Magnetic Field?

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SUMMARY

The discussion focuses on calculating the induced electromotive force (emf) and current in a flat coil of wire subjected to a changing magnetic field. The coil, consisting of 200 turns and an area of 0.01 m², experiences a uniform magnetic field of 0.500 T that is turned off over 200 ms. The average induced emf is calculated to be -5.00 V, resulting in an induced current of 0.20 A through a resistance of 25.0 Ω, generating a power output of 1.00 W. The induced magnetic field direction is towards the observer, and the current flows anticlockwise.

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Homework Statement


You are looking down at a flat coil of 200 turns of wire. It encloses an area of 10.0 cm by 10.0 cm. This coil is immersed in a uniform magnetic field of 0.500 T that penetrates the entire area. The field is pointing up towards you, the observer. The field is then shut off so that it drops to zero in 200.0 ms. The resistance in the coil of wire is 25.0 .

a) What is the average induced emf?
b) In what direction is the induced magnetic field?
c) What is the direction of the induced current?
d) What is the magnitude of the induced current?
e) What power has been generated in this circuit?

Homework Equations


o = B(A)Cos
s= - N(o)/t
I = V/R
P = VI[/B]

The Attempt at a Solution


a) o =(0.500T)(0.01m^2)(Cos 0o)
o = 0.005 Wb
s = - (200)(0.005Wb)/(0.2s)
= -5.00v[/B]

b) Induced magnetic filed is pointing towards me.

c) Anticlockwise

d) I = 5.00V/25.0(ohm)
= 0.20 A

e) P = (0.20A)(5.00V) = 1.00 W
 
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This is first time trying out here, so I hope I didn't miss anything.
 
Last edited:

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