What is the Initial Speed of a Baseball Thrown at a 45° Angle?

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Homework Help Overview

The problem involves determining the initial speed of a baseball thrown at a 45° angle, with a specified horizontal distance of 250 ft. The context is rooted in kinematics and projectile motion.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the components of velocity and the equations of motion relevant to projectile motion. There are questions about how to incorporate gravity into the equations and how to set up the problem correctly.

Discussion Status

The discussion is active, with participants providing guidance on setting up equations based on horizontal and vertical displacements. There is acknowledgment of the need to solve a system of equations involving initial velocity and time, but no consensus on the next steps has been reached.

Contextual Notes

Some participants express uncertainty about the mathematical notation and approach, indicating varying levels of familiarity with the topic. There is a mention of using different units for acceleration based on the context of the problem.

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Homework Statement



A baseball player throws a ball a distance of 250 ft. If the ball is released at an angle of 45°with the horizontal, find its initial speed.

Homework Equations





The Attempt at a Solution


I don't know where to begin. All i know is that speed is the norm of velocity. Help?
 
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Suppose the initial speed is v0. What are the vertical & horizontal components of the velocity.
 
x=(v0cos 45°)t
y=(v0sin 45°)t
 
close. You forgot that the y equation has acceleration due to gravity, so that's \frac{-9.8}{2}t^{2}.

And is that how I'm supposed to do math equations here? Cuz I am relatively new (I signed up earlier, I just never used it till now).
 
Yeah, that's how you do it. :smile: And thank you. I should use (32/2)t2 since the unit is feet. Correct?
 
oh yeah, sorry but that, but glad I could help. :smile:
 
So what do i do next? Differentiate?
 
oh i thought you got it. Sorry. You know that x displacement is 250 ft, and y displacement is 0. If you plug that in, you'll find you have a system of two equations with two variables--initial velocity and time. I'm sure you can solve from there. :wink:
 
Thank you so much! :smile:
 

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