- #61
builder_user
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gneill said:
l=0.012
What is the instantaneous value of UL after commutation?
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SUMMARY
The discussion focuses on calculating the instantaneous voltage UL across an inductor after commutation in a circuit involving resistors and a current generator. Participants clarify the use of both classical and operator methods, emphasizing the importance of understanding the circuit's behavior before and after the switch is thrown. Key parameters include K1, K2, K3, and the relationships between resistances R1, R2, R3, and R4. The consensus is that UL can be determined using the Norton equivalent circuit method, which simplifies the analysis of the circuit's response to changes in state.
PREREQUISITES- Understanding of inductor behavior in DC circuits
- Familiarity with Norton and Thevenin equivalent circuits
- Knowledge of circuit analysis techniques, including differential equations and Laplace transforms
- Basic concepts of commutation in electrical circuits
- Learn how to derive Norton equivalents for complex circuits
- Study the application of Laplace transforms in circuit analysis
- Explore the properties of inductors during transient states in DC circuits
- Practice solving differential equations related to circuit behavior during commutation
Electrical engineering students, circuit designers, and professionals involved in analyzing transient responses in electrical circuits will benefit from this discussion.
l=0.012
- #62
gneill
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builder_user said:
If you say so. In your first post you had:
K1=1.2
L = 10*K1
You did not indicate units (for anything!) so I assumed Ohms for resistances and Henries for inductance.
- #63
- #64
builder_user
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gneill said:
I forgot.In every task I have millihenries and so I've not written it there.
- #65
gneill
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- #66
gneill
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builder_user said:
Okay. Perhaps in future you should just state the component values. All the K multipliers and assumed units is confusing.
- #67
builder_user
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gneill said:
Thevenin equivalent after commutation?Or at the moment of commutation?One of the equivalents that was found before?Or not found in this topic?
- #68
gneill
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builder_user said:
After the switch closes, so yes, after commutation.
The circuit at the moment the switch closes remains the same thereafter.
It's only the initial conditions (the existing current in the inductor) that makes the moment of commutation special.
- #69
builder_user
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How to do inverse Laplace transform in MathCAD?
- #70
gneill
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builder_user said:
Select the 's' variable and then Symbolics --> Transform --> Inverse Laplace.
- #71
builder_user
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Thanks.
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