What is the kinetic energy of the proton?

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SUMMARY

The kinetic energy of a proton moving towards an infinitely long line of charge with a linear charge density of λ = 3.00 pC/m is calculated using the formula K = 0.5mv², resulting in a value of 3.34×10−21 J. To determine how close the proton approaches the line of charge, the work-energy principle is applied, where the work done equals the change in kinetic energy. The challenge arises in calculating the electric potential energy between a point charge and a line of charge, as standard equations for point charges do not apply. The discussion highlights the need for a specific equation to relate the potentials in this scenario.

PREREQUISITES
  • Understanding of kinetic energy calculations (K = 0.5mv²)
  • Familiarity with electric potential energy equations (U = k(q1q2)/r)
  • Knowledge of work-energy principles (W = Kfinal - Kinitial)
  • Basic concepts of electric fields generated by line charges (E(line of charge) = (λ/(2πε₀)) * (1/r))
NEXT STEPS
  • Research the derivation of electric potential energy equations for a point charge near a line of charge.
  • Learn about the work-energy theorem in the context of electric fields.
  • Study the behavior of charged particles in electric fields, focusing on turning points.
  • Explore advanced calculus techniques for deriving equations related to electric potentials.
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding the dynamics of charged particles in electric fields.

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Homework Statement



An infinitely long line of charge has linear charge density λ = 3.00 pC/m. A proton is at
a distance d = 14.5 cm from the line and moving directly toward the line at v = 2.00 km/s.
a. (3 points) What is the kinetic energy of the proton?
b. (15 points) How close does the proton get to the line of charge?

Homework Equations



K=.5mv2
E(line of charge)=(\lambda/(2\Pi\epsilonsubnought))*1/r
W=Kfinal-Kinitial
W=Uinitial-Ufinal
U=k(q1q2)/r

The Attempt at a Solution



First let me apologize for my lack of understanding how to input formulas into the forum. I found the latex reference tool thing but when I click something it just inserts a bunch of garbletygoop that makes my head explode a little. Yes, garbletygoop.

Part a is just a simple application of the kinetic energy equation, yielding 3.34×10^−21 J. This part is just a lead in for how to work part b. To find out how close the proton comes to the line of charge, I realized that we are really looking for the turning point of the proton, or the point at which kinetic energy equals zero. Since W=Kfinal-Kinitial, this means the work done is -Kinitial, which we just solved for in part a.

Next I plugged this into the equation W=Uinitial-Ufinal. So, -Kinitial=Uinitial-Ufinal. I know the distance (r) for the Uinitial equation, and the distance (r) for the Ufinal equation is my variable. Seemed pretty straight forward. But then I realized that my electric potential energy equations were for two point charges, not for a point charge and a line of charge. I can find no such equation, and honestly my calculus skills are not such that I can derive one of my own. Suggestions?
 
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The assumption is that the line generates a certain potential (which you should have/be able to calculate) throughout space and that the proton moves inside that potential. You are not supposed to take into account the potential that the proton creates when you work out its equations of motion.

In any case, since the equation that relates the potentials to the charges is linear, the potential of a line of charge and a point charge is a sum of the potentials of each.

Also, if you were needed to calculate the potential that the proton creates in space as it moves, you would have to take into account that it accelerates and thus creates radiation - and that isn't an electrostatic problem anymore.
 

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