What is the Laplace Transformation of cos^2t?

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SUMMARY

The Laplace transformation of cos²(t) can be computed using the integral formula \(\mathcal{L}(s) = \int_0^{\infty} e^{-st} \cos^2(t) \, dt\). This integral simplifies to \(\frac{1}{2} \int_0^{\infty} e^{-st} (\cos(2t) + 1) \, dt\), which can be further broken down into two separate integrals. The second integral, \(\int_0^{\infty} e^{-st} \, dt\), evaluates to \(-\frac{1}{s}\) when limits are applied from infinity to zero, providing a definitive solution for the Laplace transformation.

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Homework Statement



Find a Lapalce transformation of
cos^2t



Homework Equations





The Attempt at a Solution


started like this
\mathcal{L}(s)=\int_0^{\infty} e^{-st}\cos^2t\mbox{d}t=\frac{1}{2}\int_0^{\infty}e^{-st}(\cos 2t+1)\mbox{d}t=\frac{1}{2}\int_0^{\infty}e^{-st}\cos 2t\mbox{d}t+\frac{1}{2}\int_0^{\infty}e^{-st}\mbox{d}t=...
but i wonder how much the last integral is going to be?

Homework Statement

 
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∫e-st=(-1/s)e-st

Now just put in the limits from ∞ to 0 and you will get the answer easily.
 

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