What is the Launch Speed of Debris Ejected from Io's Volcanoes?

Click For Summary
SUMMARY

The launch speed of debris ejected from Io's volcanoes can be calculated using conservation of energy principles. The relevant equation is derived from Newton's Law of Gravitation, specifically: mg_{Io}h = (mv^2)/2, leading to v^2 = 2g_{Io}h. After calculations, the initial velocity on Io was determined to be approximately 92.3469 m/s^2, which translates to a maximum height of about 92 km if the debris were ejected on Earth. The calculations confirm that the gravitational acceleration on Io is crucial for determining the launch speed.

PREREQUISITES
  • Understanding of Newton's Law of Gravitation
  • Knowledge of conservation of energy principles
  • Familiarity with gravitational acceleration calculations
  • Basic algebra for solving equations
NEXT STEPS
  • Learn about gravitational acceleration on different celestial bodies
  • Explore the concept of conservation of energy in physics
  • Study the equations of motion under constant acceleration
  • Investigate volcanic activity on other moons and planets
USEFUL FOR

Astronomers, physicists, and students studying planetary science or astrophysics will benefit from this discussion, particularly those interested in the dynamics of volcanic activity on celestial bodies.

dREAPER
Messages
8
Reaction score
0
Jupiter's moon Io has active volcanoes (in fact, it is the most volcanically active body in the solar system) that eject material as high as 500km (or even higher) above the surface. Io has a mass of 8.94×10^22 [kg] and a radius of 1815km . Ignore any variation in gravity over the 500km range of the debris.

How high (in km) would this material go on Earth if it were ejected with the same speed as on Io?

I've calculated g from g = GM/R^2. What equation would I use to calculate the launch speed, v_0, for y= 500,000 m?
 
Physics news on Phys.org
Perhaps consider conservation of energy:

mg_{Io}h = \frac{mv^2}{2} \implies v^2 = 2g_{Io}h

Where g_{Io} is the acceleration due to gravity on Io.
 
Coto said:
Perhaps consider conservation of energy:

mg_{Io}h = \frac{mv^2}{2} \implies v^2 = 2g_{Io}h

Where g_{Io} is the acceleration due to gravity on Io.

I don't think we've covered that equation yet. Anything else that you can think of? This chapter covers Newton's Law of Gravitation.
 
You can derive this equation under constant acceleration considerations, but the result is the same. Specifically, the equation is:

2a\Delta y = v_f^2 - v_0^2

In your situation you should see that you know what a is and you know what v_f is.
 
V_f = 0 since it's falling back down?
I plugged my values, and got 55.4223 km. Wasn't correct though. Is my v_f value correct?
 
At the maximum height right before it starts to fall down the velocity should be zero, so yes v_f = 0.

Please write out what you used for your equation replacing a and v_f with what they should be.

What do you find for g_{Io}?

What do you find the initial velocity to be on Io?

What equation do you use to solve for how high it goes on the Earth?
 
g= G_m/R^2 which came out to 1.81*10^6 m/s^2

From there I plugged my variables into 2a\Delta y = v_f^2 - v_0^2

2(-1.81*10^6) 500,000 = 0 - v_f^2 = 1.08*10^6 m/s

Then I replaced a with g of earth, 9.81, since I calculated v_0.

2(-9.81) (delta y) = 0 - (1.08*10^6) = 55.4223 km
 
It looks good dREAPER. Please check over your units (does your answer for g_{Io} make sense?) and please check over your calculations one more time (what is v_0?)

You should end up with ~92km.
 
Coto said:
It looks good dREAPER. Please check over your units (does your answer for g_{Io} make sense?) and please check over your calculations one more time (what is v_0?)

You should end up with ~92km.

Ahh thank you. I missed the units for gravity (it was in km, not m). Calculated it and got 92.3469 m/s^2. Was correct.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
6K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
Replies
2
Views
8K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
1
Views
5K
Replies
5
Views
9K
  • · Replies 7 ·
Replies
7
Views
11K
Replies
8
Views
4K
  • · Replies 14 ·
Replies
14
Views
3K