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let an = \frac{(2n+1)}{(3n+7)}. Prove direct from definition that an\rightarrow2/3.
Any help would be appreciated.
Cheers
Any help would be appreciated.
Cheers
That's the simplest way of finding the limit but it doesn't "prove from the definition".AUMathTutor said:Here's an idea... as long as n isn't zero, the following two things are the same:
(2n+1)/(3n+7) = [(2n)(1+1/2n)]/[(3n)(1+7/3n)]
What happens as the n's get bigger and bigger to the terms 1/2n and 7/3n?