What is the limit of g'(x) on the interval (a, ∞) as x approaches infinity?

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SUMMARY

The limit of g'(x) as x approaches infinity on the interval (a, ∞) is determined by the behavior of the function g(x). If g(x) is decreasing on this interval, then it is established that lim_{x→∞} g'(x) < 0. For instance, if g(x) is defined as g(x) = ax, where a is a negative constant, then g'(x) equals a for all x, resulting in a limit of a. Without additional information about g(x), the limit could represent any negative number.

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Sethka
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When a question asks along the lines of :
"If a function (g) is decrasing on the interval {x,x)...What would the limg'(x) be (As it approaches infinity)"

What are they looking for? and whatequation am I using? I'm not looking for too much info on how to do, but which direction should I go in? I'm not sure what topic this would lie in.
 
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If g(x) is decreasing on the interval, say [tex]x\in \[ a,\infty)[/tex] then, unless you know more about the function g(x), all you can say is [tex]\lim_{x\rightarrow\infty}g^{\prime}(x)<0,[/tex] at least that I can tell.
 
"decreasing on the interval {x, x)" makes no sense. In any case, it order to talk about a limit at infinity, we would have to know what happens on some unbounded interval, say [itex](a, \infty)[/itex] as benorin said. And you still can't answer the question except as he said.

For example, if g(x)= ax, with a any negative number, then g'(x)= a for all x and so has limit a. Without more information about g, the limit could be any negative number.
 

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