What is the limitation of using the discriminant to find global extrema?

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Homework Help Overview

The discussion revolves around the limitations of using the discriminant in the context of finding global extrema for the function f(x,y) = .25x^2 + 5y^7 + 6y^2 - 3x. The original poster expresses confusion regarding the results obtained from their calculations and the implications of the discriminant.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to find global extrema by calculating partial derivatives and using the discriminant, leading to a critical point. They question why their mathematical process does not align with the conclusion about the absence of global extrema. Participants explore the distinction between local and global extrema and the role of the discriminant in this context.

Discussion Status

Participants are actively discussing the nature of the discriminant, clarifying that it indicates local extrema rather than global ones. There is an exploration of what defines the neighborhood around a critical point and how this relates to the behavior of the function at larger scales.

Contextual Notes

There is an emphasis on the properties of derivatives and their implications for local behavior, as well as the influence of higher derivatives on determining the boundaries of neighborhoods around critical points. The discussion acknowledges the complexity of the function and the need for careful consideration of its behavior at infinity.

1MileCrash
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Homework Statement



I really, really don't understand. My work shows one thing, and a simple look at the function shows another.

f(x,y) = .25x^2 + 5y^7 + 6y^2 - 3x

Find global max and min if they exist.

Homework Equations





The Attempt at a Solution



Took partial derivatives, solved each one for 0.

.5x - 3 = 0 => x = 6
35y^6 + 12y = 0 => y = 0

So a critical point is at (6,0), period.

Discriminant comes out to be

[.5][210y^5 + 12] - 0

Which comes out to be 6, since y = 0.

Therefore the discriminant is > 0, and the partial wrt x is > 0, so a global min occurs at (6,0). Period.



But wait! I submit this answer, and it basically says "nah, forget all that math crap. As y grows without bound, so does the function, so no global max or min."

?

Shouldn't the normal process lead me to that conclusion SOME HOW?
 
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The discriminant doesn't tell you anything about whether it is a global max or min. It tells you whether is a local max or min.
 
Dick said:
The discriminant doesn't tell you anything about whether it is a global max or min. It tells you whether is a local max or min.

I see...

but, why? and furthermore, local to what region?
 
1MileCrash said:
I see...

but, why? and furthermore, local to what region?

Local to the neighborhood of the critical point. And why? Because derivatives tell about the properties of a function near the point where you evaluate them, they don't tell you about what happens far away.
 
Dick said:
Local to the neighborhood of the critical point. And why? Because derivatives tell about the properties of a function near the point where you evaluate them, they don't tell you about what happens far away.

That makes sense. What determines the boundaries of the neighborhood of the critical point?
 
1MileCrash said:
That makes sense. What determines the boundaries of the neighborhood of the critical point?

It depends on the class of function you are dealing with. In this case it would be the higher derivatives. But that's not even important. The big point is just that the discriminant only tells you about local properties. Let's just say, "some neighborhood".
 
Dick said:
It depends on the class of function you are dealing with. In this case it would be the higher derivatives. But that's not even important. The big point is just that the discriminant only tells you about local properties. Let's just say, "some neighborhood".

Got it, thanks a lot!
 

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