What is the Magnetic Field Strength of a Magnetron at a Resonant Frequency?

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SUMMARY

The discussion focuses on calculating the magnetic field strength of a magnetron at a resonant frequency of 2.82×1010 s-1. The relevant equations include f = qv * b, where q is the electron charge (-1.6E-19 C), v is the velocity, and b is the magnetic field. To find the velocity, participants suggest using the relationship between period (T = 3.55×10-11 s) and circular motion, specifically the equation for centripetal force. The solution requires determining the radius of the electron's orbit.

PREREQUISITES
  • Understanding of magnetron operation and electron dynamics
  • Familiarity with the equations of motion in circular paths
  • Knowledge of centripetal force and its relationship to magnetic force
  • Basic grasp of electromagnetic theory and resonant frequency concepts
NEXT STEPS
  • Learn about the derivation of the centripetal force equation in circular motion
  • Study the relationship between frequency, period, and velocity in circular motion
  • Explore the principles of magnetron design and operation
  • Investigate the effects of varying magnetic field strength on electron behavior
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Students studying electromagnetism, electrical engineers working with microwave technology, and physicists interested in particle dynamics in magnetic fields.

Hellphish
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Homework Statement



A magnetron is a microwave source in which a "bunch" of electrons travel on a circular orbit in a uniform magnetic field. As the electrons pass the electrodes, a high-frequency alternating voltage difference occurs. Suppose the resonant frequency is f = 2.82×10^10 s-1; that is, the electron period of revolution is T = 3.55×10^-11 s. What is the corresponding strength of the magnetic field?
The electron charge is -1.6E-19 C and the electron mass is 9.1E-31 kg.

Homework Equations



f=qv * b
where q is the charge, v is the velocity, and b is the magnetic field

The Attempt at a Solution



I think I need to set a centripetal force equal to the magnetic force. The only equation I know for centripetal force is f=m(v^2 / r) and I'm not sure how to solve that with the period. I'm really just not sure if I'm even going about this right or how I can solve for v and r. Any help would be appreciated.
 
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Hellphish said:

Homework Statement



A magnetron is a microwave source in which a "bunch" of electrons travel on a circular orbit in a uniform magnetic field. As the electrons pass the electrodes, a high-frequency alternating voltage difference occurs. Suppose the resonant frequency is f = 2.82×10^10 s-1; that is, the electron period of revolution is T = 3.55×10^-11 s. What is the corresponding strength of the magnetic field?
The electron charge is -1.6E-19 C and the electron mass is 9.1E-31 kg.

Homework Equations



f=qv * b
where q is the charge, v is the velocity, and b is the magnetic field

The Attempt at a Solution



I think I need to set a centripetal force equal to the magnetic force. The only equation I know for centripetal force is f=m(v^2 / r) and I'm not sure how to solve that with the period. I'm really just not sure if I'm even going about this right or how I can solve for v and r. Any help would be appreciated.

You are only missing one equation (which is quite simple). Consider a particel going in a circle of radius r. If it takes a time T to go around once, what is the speed of the particle?
 
Oh wow, I didn't even think of that. Thanks.
 

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