A 184-kg crate is being pushed across a horizontal floor by a force P that makes an angle of 15.2 ° below the horizontal. The coefficient of kinetic friction is 0.264. What should be the magnitude of P, so that the net work done by it and the kinetic frictional force is zero? Ok so this is what Ive come up with... w=mg= (184)(9.8) = 1803.2 N Fk= Uk * Fn = (.264)(1803.2) = 476.05 Fn equals w (but opposite, right? Then... Fnet of y = 0 Fnet of x = Pcos(15.2) - Fk = 0 so... P = 476.05 / cos(15.2) = 493.30 N. But Im told thats the wrong answer!! Why??? Please help me! Thank you!