What is the Maximum Inclination of a 3D Plane and its Equation in the XY Plane?

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SUMMARY

The maximum inclination of a 3D plane represented by the equation Ax + By + Cz = 0 is achieved by a plane that is perpendicular to the reference plane. This perpendicular relationship implies that if the slope of the intersection line is denoted as m, the slope of the line representing maximum inclination is calculated as -1/m. In cases where the slope m equals zero, indicating a horizontal line, the corresponding perpendicular line is vertical and does not possess a defined slope.

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  • Understanding of 3D plane equations (Ax + By + Cz = 0)
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cptolemy
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Hi,

If I have a 3D plane Ax+By+Cz=0, and I know the line equation of its intersection with the reference plane, what is the maximum inclination a point can have and what is its equation in the xy plane?

Is it perpendicular to the intersection? That is , if the slope of the intersection line is m, the max will be given by the line with a slope of -1/m?

This is embarassing...

Cheers,

Kepler
 
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If I understand what you mean by "inclination" then, yes, the plane with maximum "inclination" to a given plane is perpendicular to it. And, yes, if a line is perpendicular to a line with (non-zero) slope m, then it has slope -1/m. Note that if m= 0, so "horizontal", then the perpendicular line is "vertical" and does not have a defined slope.
 

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