What Is the Maximum Speed to Navigate a Banked Curve Without Sliding?

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The discussion centers on calculating the maximum speed for a car navigating a banked curve with a radius of 70.0 m and a banking angle of 13.0 degrees, given a static friction coefficient of 1.0. The initial attempt at the solution using the formula provided resulted in an incorrect speed of 26.49 m/s. A suggestion was made to reevaluate the free body diagram (FBD) and the force equations, as the normal and static friction forces have both radial and vertical components. After further analysis, the original poster identified their mistake and expressed gratitude for the assistance. The conversation highlights the importance of accurately applying physics principles in problem-solving.
man00war
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Homework Statement



A concrete highway curve of radius 70.0 m is banked at a 13.0 degree angle.
What is the maximum speed with which a 1900 kg rubber-tired car can take this curve without sliding? (Take the static coefficient of friction of rubber on concrete to be 1.0.)

Homework Equations



the equation that i was told to use is

vmax=sqrroute(R*g*( (1 + Fs*cotan(13)) /cotan(13)-Fs) )

The Attempt at a Solution


so i plug in my numbers vmax= (70*9.8)* (1+1*cotan(13))/(cotan(13)-1)

i get the sqrout of (686*1.023)

which tells me vmax equals 26.49

this is wrong can anyone help?
h
 
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I didn't check to see if that equation matches the one I came up with( and I know is right since I have the same problem in my textbook)..but if its consistently giving you the wrong answer you should probably go back to your fbd and try again. The normal and static friction forces both have radial and z components and the force of gravity is acting on the car in the downward z direction. When I solved my force equations, I eliminated n...so try that.
 
i found what i was doing wrong thanks for your help
 
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