Circular Motion and Banked Curves

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SUMMARY

The discussion focuses on calculating the maximum speed of a 1500 kg rubber-tired car navigating a banked curve with a radius of 60.0 m and a banking angle of 11.0 degrees. The static coefficient of friction between rubber and concrete is given as 1.0. Key forces include gravity, normal force, and friction, with the centripetal force being a resultant force rather than a direct acting force. The solution involves analyzing the forces to determine the normal reaction and frictional force acting on the car.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with free body diagrams (FBD)
  • Knowledge of centripetal acceleration and forces
  • Basic principles of friction and static coefficients
NEXT STEPS
  • Calculate the maximum speed using the formula for centripetal force on a banked curve
  • Explore the effects of varying the banking angle on vehicle dynamics
  • Investigate the role of different surface materials on friction coefficients
  • Learn about the implications of vehicle weight on cornering performance
USEFUL FOR

Physics students, automotive engineers, and anyone interested in the dynamics of vehicles on curved paths will benefit from this discussion.

erin.grae
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Homework Statement


A concrete highway curve of radius 60.0 m is banked at a 11.0 degree angle. What is the maximum speed with which a 1500 kg rubber-tired car can take this curve without sliding? (Take the static coefficient of friction of rubber on concrete to be 1.0.)


Homework Equations


w f 2 = w i2* t + 1.2 * alpha * t
theta f - theta i = w i t + t/2 alpha t 2

The Attempt at a Solution



Okay, I drew a picture of the problem and I tried to find all the forces acting on the car but I really don't think I've got them all. I know there's the usual gravity, normal force, and centripetal acceleration but I'm not sure if the equations I referenced above are even really relevant.
 
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In your FBD, centripetal force is not to be on there, centripetal force is a resultant force.

The resultant normal force (perpendicular to the plane) is zero. You should now be able to find the normal reaction.

Friction=μR.

If the car slides down the plane, then friction acts up the plane. What do the resultant of these two force give?
 

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