What Is the Maximum Speed to Navigate a Banked Curve Without Sliding?

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SUMMARY

The maximum speed at which a 1900 kg rubber-tired car can navigate a banked curve with a radius of 70.0 m and a banking angle of 13.0 degrees is calculated using the formula vmax = sqrt(R*g*((1 + Fs*cotan(θ))/cotan(θ) - Fs)). The correct application of this formula, considering the static coefficient of friction of rubber on concrete as 1.0, yields a maximum speed of 26.49 m/s. However, the initial calculation was incorrect due to misapplication of the forces involved. A thorough reevaluation of the free body diagram (FBD) and the force equations is essential for accurate results.

PREREQUISITES
  • Understanding of centripetal force and banking of curves
  • Familiarity with static friction and its coefficient
  • Knowledge of trigonometric functions, particularly cotangent
  • Ability to construct and analyze free body diagrams (FBD)
NEXT STEPS
  • Review the derivation of the banking curve equations in physics
  • Study the effects of friction on motion in circular paths
  • Learn how to construct and interpret free body diagrams for complex systems
  • Explore advanced applications of centripetal force in real-world scenarios
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and circular motion, as well as educators seeking to clarify concepts related to banking curves and frictional forces.

man00war
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Homework Statement



A concrete highway curve of radius 70.0 m is banked at a 13.0 degree angle.
What is the maximum speed with which a 1900 kg rubber-tired car can take this curve without sliding? (Take the static coefficient of friction of rubber on concrete to be 1.0.)

Homework Equations



the equation that i was told to use is

vmax=sqrroute(R*g*( (1 + Fs*cotan(13)) /cotan(13)-Fs) )

The Attempt at a Solution


so i plug in my numbers vmax= (70*9.8)* (1+1*cotan(13))/(cotan(13)-1)

i get the sqrout of (686*1.023)

which tells me vmax equals 26.49

this is wrong can anyone help?
h
 
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I didn't check to see if that equation matches the one I came up with( and I know is right since I have the same problem in my textbook)..but if its consistently giving you the wrong answer you should probably go back to your fbd and try again. The normal and static friction forces both have radial and z components and the force of gravity is acting on the car in the downward z direction. When I solved my force equations, I eliminated n...so try that.
 
i found what i was doing wrong thanks for your help
 

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