What Is the Maximum Transverse Velocity at x=0 for a Moving Wave Pulse?

Click For Summary
SUMMARY

The discussion focuses on calculating the maximum transverse velocity of a wave pulse described by the function f(x) = y0/[1 + (x/a)^2] at the point x=0. The phase velocity is given as v = 210 m/s, with parameters y0 = 1.3 cm and a = 5 cm. To find the transverse velocity, participants suggest substituting x with (x - vt) and taking the partial derivative with respect to time. The transverse velocity is defined as the vertical displacement of the wave, which is perpendicular to the direction of propagation along the x-axis.

PREREQUISITES
  • Understanding of wave mechanics and wave pulse behavior
  • Knowledge of partial differentiation and its application in physics
  • Familiarity with the concepts of phase velocity and transverse velocity
  • Basic skills in mathematical modeling of wave functions
NEXT STEPS
  • Study the mathematical derivation of wave pulse velocities
  • Learn about the principles of wave propagation in different media
  • Explore the concept of transverse and longitudinal waves in physics
  • Investigate the application of partial derivatives in physical systems
USEFUL FOR

Students of physics, particularly those studying wave mechanics, as well as educators and anyone involved in teaching or learning about wave dynamics and their mathematical representations.

Lavabug
Messages
858
Reaction score
37

Homework Statement


I'll try to translate the problem as faithfully as I can:

A wave pulse moves along the positive OX axis. Its form when t=0 is
f(x) = y0/[1 + (x/a)^2]
Find the expression for the transverse velocity as a function of x and t.
At the point x=0, what will be its max transverse velocity, if v = 210m/s (I assume this is phase velocity), y0 = 1.3cm, and a = 5cm?


The Attempt at a Solution


For the first part, should I substitute x for (x -vt) and take the partial with respect to t of the whole function? That should give me the expression for "vertical" velocity. Then I'd simply substitute x=0, v, y0 and a to get the velocity?

I thought "transverse" meant along the x-axis. The question looks really ambiguous and misleading but I think that's what's being asked, any thoughts?
 
Physics news on Phys.org
Transverse means that the displacement of the "disturbance" is perpendicular to the direction of propagation. This wave travels along the x axis, in positive direction, the displacement is in the y direction. Imagine that the wave travels along a string, and the particles of the string move up and down. You can find the vertical velocity as you outlined. Do the differentiation with respect to time, substitute x=0 and the given values of v and y0, and find the maximum.

ehild
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
13
Views
2K
  • · Replies 13 ·
Replies
13
Views
927
  • · Replies 10 ·
Replies
10
Views
5K
Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
7K
  • · Replies 1 ·
Replies
1
Views
2K