The discussion centers on the interpretation of the notation "+:0" in the context of limit calculations using the HP 50G emulator. Users clarify that the limit of the expression ## \lim\limits_{x\to\infty} [2^{2x} \times (\frac13)^x + (\frac12)^{2x}\times (\frac23)^x ]## approaches +∞, indicating that "+:0" signifies approaching the limit from the right. References to the HP 50G User Guide reveal that while "+0" and "-0" are documented, "+:0" lacks explicit mention. Additionally, the emulator's limitations are highlighted, noting that stack overflow occurs when maxR exceeds +9E499 or minR falls below -9E499.
PREREQUISITESStudents, programmers, and mathematicians who utilize the HP 50G calculator for limit calculations and seek to understand advanced notation in mathematical expressions.
Would you tell me on which page(page number), I shall get the information about +:0 ?malawi_glenn said:
Can you make an effort yourself? I just suggested that the manual would contain the information you were looking for.WMDhamnekar said:
I don't think that makes any sense, as the limit is as x approaches infinity. And per @malawi_glenn, the limit itself is infinity.jedishrfu said:
That means, in our context, the limit is slightly higher than 0 when ## x \to \infty## which is wrong. hp 50g emulator gave wrong answer because its stacks are overflowed when maxR > +9E499 or minR < -9E499.jedishrfu said:
In our finite world (Universe?) I doubt it makes much difference.WMDhamnekar said:
