What is the Median of a Density Function and How Can I Solve for It?

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The discussion focuses on finding the median of a given probability density function, f(x) = (4/81)x(9-x^2) for 0 <= x <= 3. The median is determined by solving the integral from m to 3 of f(x) equating it to 1/2. The user initially set up the integral correctly but faced challenges in solving for m. A suggestion was made to substitute u = m^2 to simplify the quadratic equation derived from the integral. The user confirmed that this approach was successful in finding the median value.
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Homework Statement


The probability density function is defined as

f(x) = (4/81)x(9-x^2) for 0 <= x <= 3
= 0 for every other value

Find the median value of the density.

Homework Equations


The median of a function is

integral from m to infinity of f(x)dx = 1/2


The Attempt at a Solution



I took the integral from m to 3 of (4/81)x(9-x^2).

This turned out to be

(18/81)x^2 -(1/81) x^4 = 1/2

I then evaluated the left hand side from m to 3 and simplified so that only the variable m is left. The equation I got was

(1/81)m^4 - (18/81)m^2 = -1/2

I know that I am suppose to solve for m in order to get the median but I'm not sure how to do this, and I am also unsure whether my procedure is correct.

Any help would be great thanks. Sorry bout the formatting I'm new to this.
 
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The integral looks okay. In the equation try setting

<br /> u = m^2 \Rightarrow u^2 = m^4<br />

Then solve the quadratic for u, and find m from that. Remember that m has to be between 0 and 3.
 
Thanks a lot, I tried that out and it works
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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