What is the Method for Finding a Cubic Function with Specific Zeros?

  • Thread starter Thread starter nanoWatt
  • Start date Start date
  • Tags Tags
    Cubic Function
Click For Summary
To find a cubic function with specific zeros, the roots are identified as f(-1)=0, f(0)=0, and f(2)=0, leading to the factors (x+1), x, and (x-2). The general form of the function is expressed as f(x) = K*(x+1)x(x-2), where K is a constant. To satisfy the condition f(1)=6, the value of K is determined to be -3, resulting in the function f(x) = -3x(x+1)(x-2). The discussion highlights the importance of using the given conditions to derive the correct function. Overall, the method involves identifying zeros, forming the function, and adjusting constants based on additional criteria.
nanoWatt
Messages
85
Reaction score
2

Homework Statement



From James Stewart's Essential Calculus Early Trancendentals, p.21 #5.

Find an expression for a cubic function f if f(1)=6 and f(-1)=f(0)=f(2)=0

Homework Equations



Used zeros of the function.

The Attempt at a Solution



I understand that the values of x (assuming it's f(x)) which make the value 0 are the zeros of the function. We want these x values to make the whole statement 0, so

since f(-1) = 0, then (x+1) is one of the zeros. Similarly (x-0) and (x-2) are zeros as well.

If I put them together, I get (x+1)(x)(x-2), but then I don't know what to do with the f(1) = 6.

The answer guide gives: f(x) = -3x(x+1)(x-2)

For some reason, the (x-0) just dropped off, and somehow f(1)=6 equates to -3x, or maybe just -3, and the x is from the (x-0).
 
Physics news on Phys.org
Putting the roots together gives you K*(x+1)(x)(x-2) where K is any constant. That still has the right roots. To determine K, put x=1 and adjust K so you get 6.
 
nanoWatt said:
If I put them together, I get (x+1)(x)(x-2), but then I don't know what to do with the f(1) = 6.

Now, f(x) = x(x + 1)(x - 2) is a function that you have arrived at from the fact that x, x + 1 and x - 2 are factors for f(x). However, these three monomials are also factors of.. let's say 2x(x + 1)(x - 2) or 4x(x + 1)(x - 2). Basically, any function of the form: f(x) = ax(x + 1)(x - 2) has those three monomials as it's factors.

so.. can you use the fact that f(1) = 6 to get the value of 'a'?? If done properly, you should get a = -3 which will match your answer...

EDIT:

goddammit.. dick beat me to it.. [no pun intended]
 
Thanks to both of you. Actually, before that was assigned to us, I went through some of the problems on my own, and tried that one. I asked the teacher about it, and she didn't seem to know how to do it. Then she assigned it to us that evening. It was the only problem in this week's homework I've had trouble with.
 
Well, of course. If you don't know how to solve a problem, give it to your students!
 
HallsofIvy said:
Well, of course. If you don't know how to solve a problem, give it to your students!

i'm going to go out and get myself a student...
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
8
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K