What is the Method for Finding a Cubic Function with Specific Zeros?

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Homework Help Overview

The problem involves finding a cubic function with specific zeros and a given value at a certain point. The function must satisfy f(1)=6 and have zeros at f(-1), f(0), and f(2).

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the identification of zeros and the construction of the function from these factors. There is an exploration of how to incorporate the condition f(1)=6 to determine a constant multiplier for the function.

Discussion Status

Some participants have suggested using the condition f(1)=6 to find a constant that adjusts the function appropriately. There is acknowledgment of multiple interpretations regarding the construction of the function and the role of the constant.

Contextual Notes

Participants note the challenge of the problem, including a lack of clarity from the instructor prior to the assignment. There are hints of frustration regarding the assignment's difficulty.

nanoWatt
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Homework Statement



From James Stewart's Essential Calculus Early Trancendentals, p.21 #5.

Find an expression for a cubic function f if f(1)=6 and f(-1)=f(0)=f(2)=0

Homework Equations



Used zeros of the function.

The Attempt at a Solution



I understand that the values of x (assuming it's f(x)) which make the value 0 are the zeros of the function. We want these x values to make the whole statement 0, so

since f(-1) = 0, then (x+1) is one of the zeros. Similarly (x-0) and (x-2) are zeros as well.

If I put them together, I get (x+1)(x)(x-2), but then I don't know what to do with the f(1) = 6.

The answer guide gives: f(x) = -3x(x+1)(x-2)

For some reason, the (x-0) just dropped off, and somehow f(1)=6 equates to -3x, or maybe just -3, and the x is from the (x-0).
 
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Putting the roots together gives you K*(x+1)(x)(x-2) where K is any constant. That still has the right roots. To determine K, put x=1 and adjust K so you get 6.
 
nanoWatt said:
If I put them together, I get (x+1)(x)(x-2), but then I don't know what to do with the f(1) = 6.

Now, f(x) = x(x + 1)(x - 2) is a function that you have arrived at from the fact that x, x + 1 and x - 2 are factors for f(x). However, these three monomials are also factors of.. let's say 2x(x + 1)(x - 2) or 4x(x + 1)(x - 2). Basically, any function of the form: f(x) = ax(x + 1)(x - 2) has those three monomials as it's factors.

so.. can you use the fact that f(1) = 6 to get the value of 'a'?? If done properly, you should get a = -3 which will match your answer...

EDIT:

goddammit.. dick beat me to it.. [no pun intended]
 
Thanks to both of you. Actually, before that was assigned to us, I went through some of the problems on my own, and tried that one. I asked the teacher about it, and she didn't seem to know how to do it. Then she assigned it to us that evening. It was the only problem in this week's homework I've had trouble with.
 
Well, of course. If you don't know how to solve a problem, give it to your students!
 
HallsofIvy said:
Well, of course. If you don't know how to solve a problem, give it to your students!

i'm going to go out and get myself a student...
 

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