What Is the Minimum Cosine Value in Trigonometric Constraints?

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SUMMARY

The minimum cosine value in the trigonometric constraints defined by the equations $\cos a + \cos b + \cos c = 1$ and $\sin a + \sin b + \sin c = 1$ is established as $-\frac{1}{4}(1+\sqrt{7})$. Both contributors to the discussion confirmed this result, indicating a consensus on the solution derived from the given constraints.

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anemone
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Here is this week's POTW:

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Let $a,\,b$ and $c$ be three real numbers such that $\cos a+\cos b+\cos c=1$ and $\sin a+\sin b+\sin c=1$.

Find the smallest possible value of $\cos a$.

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I get ##-\frac 14(1+\sqrt 7)##.
Hint:

Combine the two constraint equations into one complex one. Visualise the minimisation of cos a in the complex plane and consider what that means for the other two points.


Write ##\alpha=\cos(a)+i\sin(a)## etc.
##\alpha+\beta+\gamma=1+i##.
Minimising cos a means getting ##\alpha## as close as possible to ##-1##, which means getting ##\beta+\gamma## as close as possible to 2+i.
Since ##|\beta|\leq 1##, ##|\gamma|\leq 1## and ##|2+i|>2##, that implies ##\beta=\gamma##.
The rest is algebra.
 
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I got the same answer.


I looked at it as the vector equation ##\vec A + \vec B + \vec C = \vec R## where ##\vec A##, ##\vec B##, and ##\vec C## are unit vectors with directions ##a##, ##b##, and ##c## respectively, and ##\vec R = \hat i + \hat j##. When ##\vec A## points as far counterclockwise from the ##x##-axis as possible, ##\vec B## and ##\vec C## have to be parallel, so we end up with a triangle where we know the length of all three sides. Then the angle ##a## can be found using the law of cosines.
[\ispoiler]
 
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