What is the Minimum Distance Between a BMW and a Camper to Avoid Collision?

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SUMMARY

The minimum distance required to avoid a collision between a BMW traveling at 39.2 m/s and a camper moving at 15.7 m/s involves calculating both the reaction time and the braking distance. The driver's reaction time is 0.26 seconds, during which the BMW continues at its initial speed. After this period, the vehicle decelerates at 3.5 m/s². The correct approach requires separating the problem into two phases: the reaction time phase and the braking phase, ensuring that the BMW's speed equals the camper's speed at the moment of potential collision.

PREREQUISITES
  • Understanding of kinematic equations, specifically V=Vo+at and X=Xo+volt+1/2at²
  • Knowledge of basic physics concepts such as reaction time and deceleration
  • Familiarity with the concept of relative speed in motion
  • Ability to perform calculations involving acceleration and distance
NEXT STEPS
  • Calculate the distance covered during the reaction time using the formula distance = speed × time
  • Determine the braking distance using the equation X = Vo*t + 1/2at²
  • Explore the implications of different deceleration rates, such as the average vehicle deceleration of -9.8 m/s²
  • Review scenarios involving relative motion to deepen understanding of collision avoidance
USEFUL FOR

Physics students, automotive safety engineers, and anyone interested in understanding the dynamics of vehicle collisions and braking distances.

jojo711
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Homework Statement


Suppose that a man driving a BMW zooms out of a darkened tunnel at 39.2 m/s. He is momentarily blinded by the sunshine. When he recovers, he sees that he is fast overtaking a camper ahead in his lane moving at the slower speed of 15.7 m/s. He hits the brakes as fast as he can (his reaction time is 0.26 s). If he can decelerate at 3.5 m/s2, what is the minimum distance between the driver and the camper when he first sees it so that they do not collide?

Homework Equations


V=Vo+at
X=Xo+volt+1/2at^2
V^2=Vo^2+2a(X-Xo)

The Attempt at a Solution


I took the second equation and plugged in the numbers [V=39.2(0.26)+1/2(3.5)(0.26^2)] and ended with the answer being 10.3103. When I put my answer in, it was wrong. Please help me!
 
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jojo711 said:

Homework Statement


Suppose that a man driving a BMW zooms out of a darkened tunnel at 39.2 m/s. He is momentarily blinded by the sunshine. When he recovers, he sees that he is fast overtaking a camper ahead in his lane moving at the slower speed of 15.7 m/s. He hits the brakes as fast as he can (his reaction time is 0.26 s). If he can decelerate at 3.5 m/s2, what is the minimum distance between the driver and the camper when he first sees it so that they do not collide?

Homework Equations


V=Vo+at
X=Xo+volt+1/2at^2
V^2=Vo^2+2a(X-Xo)

The Attempt at a Solution


I took the second equation and plugged in the numbers [V=39.2(0.26)+1/2(3.5)(0.26^2)] and ended with the answer being 10.3103. When I put my answer in, it was wrong. Please help me!

Your chosen equation does not address the problem as stated. The 0.26s time span is the driver's reaction time -- the time between when he recognizes the danger and when he actually does something about it. No braking is happening during that time! No velocity change is taking place during that time!

You'll have to consider the problem in two parts: the 'reaction time phase' and the 'braking phase'.
 
Hint: The speed of the BMW must just equal the speed of the camper just the split second it catches it. That defines a time.

As an aside, the brakes on the BMW are not working properly. The average vehicle has an acceleration rate under maximum braking of -1g which is -9.8 m/s^2.
 

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