Brave Fish launching himself in a cannon

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SUMMARY

The discussion focuses on the physics problem of a fish launching from a 6 cm cannon at an initial velocity of 6.5 m/s. The calculated acceleration during the launch is determined to be 361.88 m/s², leading to a time in the cannon of 0.02 seconds. An alternative method using the average velocity formula is suggested for a more straightforward solution. The key takeaway is that the gravitational acceleration should not be added to the upward acceleration during the calculation.

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  • Familiarity with concepts of acceleration and initial velocity
  • Knowledge of gravitational acceleration (9.8 m/s²)
  • Ability to manipulate algebraic equations for solving physics problems
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Homework Statement


The brave fish launches himself from a 6 cm cannon straight up in the air. When he leaves the cannon he is traveling at 6.5 m/s. assume constant acc while in the cannon.
How long was the fish in the cannon?



Homework Equations


v^2=Vo^2+2ax
X= Xo + volt + 1/2at^2
X=height
Xo=initial height
Vo=initial velocity
t=time



The Attempt at a Solution


6.5^2=0^2+2a(.06)
a=352.08m/s^2
352.08=u-9.8 (u=up acc)
u=361.88m/s^2

x=1/2at^2
.06=1/2(361.88)t^2
t=.02sec
 
Physics news on Phys.org
Yes, but do not add 'g' to the acceleration. You can get the same result more easily by using [itex]x = [(v_o + v_f)/2]t[/itex].
 

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