What is the minimum distance in which the car will stop?

  • Thread starter Thread starter debbie18
  • Start date Start date
  • Tags Tags
    Car Minimum
AI Thread Summary
To determine the minimum stopping distance of a car traveling at 34.5 mi/h, one must consider the coefficients of friction for both wet and dry conditions. For a rainy day with a static friction coefficient of 0.064, the stopping distance can be calculated using the formula that incorporates gravitational acceleration. Conversely, when the surface is dry with a coefficient of 0.675, the stopping distance will be significantly shorter. Understanding static and kinetic friction is crucial for solving these problems effectively. Accurate calculations will yield the required stopping distances for both scenarios.
debbie18
Messages
6
Reaction score
0
Can someone tell me how to do this question:
1. a) A car is traveling at 34.5 mi/h on a horizontal highway. The acceleration of gravity is 9.8 m/s^2. If the coefficient of static friction between road and tires on a rainy day is 0.064, what is the minimum distance in which the car will stop?
b) What is the stopping distance when the surface is dry and the coefficient of friction is 0.675.
Thanks.
 
Last edited by a moderator:
Physics news on Phys.org
debbie18 said:
Can someone tell me how to do this question:
1. a) A car is traveling at 34.5 mi/h on a horizontal highway. The acceleration of gravity is 9.8 m/s^2. If the coefficient of static friction between road and tires on a rainy day is 0.064, what is the minimum distance in which the car will stop?
b) What is the stopping distance when the surface is dry and the coefficient of friction is 0.675.
Thanks.

What have you done so far?

The following URL might help you with the definition of static and kinetic friction, if that happens to be your problem (it's hard to say, because you haven't attempted to explain how you tried to solve the problem).

http://hyperphysics.phy-astr.gsu.edu/hbase/frict2.html
 

Thread 'Derivation of Hamilton's Principle: Questions'

I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
View full post »

Similar threads

Car - brake locking, stopping distance
Replies
24
Views
5K
What forces oppose a car's motion when braking?
Replies
8
Views
4K
How do you know which way friction points?
Replies
12
Views
2K
What factors affect car braking distance?
Replies
7
Views
4K
Car Acceleration - Torque Balance
Replies
12
Views
2K
Friction & Cars: Understand Acceleration, Constant Velocity & Brakes
Replies
1
Views
2K
Car behaviour on a straight road with a rolling road
Replies
8
Views
2K
Is a car's top speed the same on a wet road?
Replies
26
Views
7K
Frictional Forces and Stopping Distance in Physics
Replies
1
Views
2K
Friction Challenge Problem - Finding Distance Required To Stop.
Replies
3
Views
3K

Hot Threads

Recent Insights

Back
Top