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What is the minimum potential difference?

  1. Nov 17, 2009 #1
    What is the minimum potential difference applied to an x-ray tube if x-rays of wavelength 0.250 nm are produced?



    E=hf
    f=c/wavelength

    f=3e8/.250e-9
    =1.2e18

    then i applied it to the first equation using plancks constant as h and my final answer came out to be 7.95e-16 KV.

    the answer is wrong. can you please help me out? thanks.
     
  2. jcsd
  3. Nov 17, 2009 #2
    half way there,

    the work done accelerating the electrons is equal to [tex] eV [/tex], but you can also find out the energy of the xrays, as you've shown, these energies should be equal.

    you worked out the energy of the xrays, not the voltage.
     
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