Electron potential/momentum problem

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Homework Help Overview

The discussion revolves around a problem related to the production of x-ray radiation through the acceleration of electrons in a vacuum. Participants are tasked with determining the potential difference required for the electrons, given a specific wavelength of the resulting x-ray photon.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between the kinetic energy of electrons and the energy of x-ray photons, questioning the appropriate equations to use. Some express confusion regarding the formulas and their application, particularly in relation to momentum and wavelength.

Discussion Status

The discussion is ongoing, with participants offering various approaches and questioning the assumptions behind the equations used. Some guidance has been provided regarding the need to relate the accelerating voltage to the energy of the x-ray photons, but no consensus has been reached on the correct method or formula.

Contextual Notes

Participants note the constraints of the problem, including the requirement to express the answer in kilovolts and the need to clarify the distinction between the momentum of electrons and photons. There is also mention of the specific values for physical constants and the conditions of the problem.

orangeincup
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Homework Statement


To produce x-ray radiation, electrons are accelerated in vacuum and aimed so as to collide with a target. Assume that all of the electron kinetic energy is converted into the energy of the x-ray photon on collision and that the wavelength of the resulting radiation is 1.24 angstroms.

Homework Equations


h^2/(2*(e)(m)(λ)^2)

The Attempt at a Solution


(6.63*10^-34)^2/(2(1.6*10^-19)(9.11*10^-31)(1.24*10^-9)^2)

=.979 V
/1000 for kV = .000979 kV. I entered this answer and it told me it was incorrect.
 
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That equation is unknown to me. Try starting out with the basic equation for the energy of the x-ray photon.
 
orangeincup said:

Homework Statement


To produce x-ray radiation, electrons are accelerated in vacuum and aimed so as to collide with a target. Assume that all of the electron kinetic energy is converted into the energy of the x-ray photon on collision and that the wavelength of the resulting radiation is 1.24 angstroms.

Homework Equations


h^2/(2*(e)(m)(λ)^2)

The Attempt at a Solution


(6.63*10^-34)^2/(2(1.6*10^-19)(9.11*10^-31)(1.24*10^-9)^2)

=.979 V
/1000 for kV = .000979 kV. I entered this answer and it told me it was incorrect.

What is the question?
You did not write any equation. What does the formula in 2 mean?
 
The question is "What potential difference must the electron be accelerated? (answer in kV) "
Enter the electron momentum in kg*m/s

My equation I found using KE=1/2mv^2, λ = h / p, and I guess I messed something up

so I have the λ=1.26, the mass of an electron, the fact it is a vaccum, the charge of an electron, planks constant. What kind of formula should I be using?

h/ λ =p
(6.63*10^-34)/(1.24*10^-10) = 5.34*10^-24 (momentum?)
 
orangeincup said:
The question is "What potential difference must the electron be accelerated? (answer in kV) "
Enter the electron momentum in kg*m/s

My equation I found using KE=1/2mv^2, λ = h / p, and I guess I messed something up

so I have the λ=1.26, the mass of an electron, the fact it is a vaccum, the charge of an electron, planks constant. What kind of formula should I be using?
You need a formula that contains the accelerating voltage.
orangeincup said:
h/ λ =p
(6.63*10^-34)/(1.24*10^-10) = 5.34*10^-24 (momentum?)
The problem asks the momentum of the electron. h/ λ =p is right if you use the wavelength of the electron, but you substituted the wavelength of the photon, so you got the momentum of the photon.
 
The kinetic energy of the electrons are used to produce the x-ray photons. So I suggest starting out with the energy of the x-ray photons. Do you know what the equation is for the energy of a photon (according to Planck and as used by Einstein to explain the photoelectric effect)?
 

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