Albert1
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Given:
$x,y,z\in\mathbb{N}\text{ and }xy+z=160$
$\text{Compute }\min(x+yz)$
$x,y,z\in\mathbb{N}\text{ and }xy+z=160$
$\text{Compute }\min(x+yz)$
Albert said:sorry the answer is not correct
the answer is correct ,try to solve it systematically pleaseOpalg said:Best I can do so far (by trial and error) is $(x,y,z) = (26,6,4)$, giving $x+yz = 50$.