1.A small 3.94 g plastic ball is suspended by a 27.9 cm long string in a uniform electric field of 3400 N/C. The acceleration of gravity is 9.8 m/s2 , and the Coulomb constant is 8.99×109 N · m2/C2. If the ball is in equilibrium when the string makes a 43.2◦ angle with the vertical as in- dicated, what is the net charge on the ball? Answer in units of μC. 2. E=F/q Fe=kq/r^2 3. Well I'm kind of lost. When they ask for the net charge, I just plugged the F, found using F=mg, and electric field into the equation E=F/q. And then I used that q and plugged it into the Fe=kq/r^2 equation, and found q. I thought that was the answer, but apparently not. I don't understand how to do the problem at ALL. please help. thanks in advance.