What is the net force acting on the truck?

Click For Summary
SUMMARY

The net force acting on the truck is determined by analyzing the forces in play: a downward gravitational force of 48 kN, an upward contact force of 48 kN, an eastward contact force of 4.5 kN, and a westward drag force of 0.9 kN. The upward and downward forces cancel each other out, resulting in a net vertical force of 0 kN. The net horizontal force is calculated by subtracting the drag force from the eastward contact force, yielding a net force of 3.6 kN directed east.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic knowledge of vector addition
  • Familiarity with forces measured in kiloNewtons (kN)
  • Ability to interpret free-body diagrams
NEXT STEPS
  • Study vector addition techniques in physics
  • Learn how to create and analyze free-body diagrams
  • Explore the concept of equilibrium in forces
  • Investigate the effects of drag force on moving objects
USEFUL FOR

Physics students, engineers, and anyone interested in understanding force dynamics and motion analysis in real-world scenarios.

lpw8340
Messages
1
Reaction score
0
1. A man is lazily floating on an air mattress in a swimming pool. If the weight of the man and air mattress together is 740 N, what is the upward force of the water acting on the system of man and mattress?




2. A truck driving on a level highway is acted upon by the following forces: a downward gravitational force of 48 kN (kiloNewtons); an upward contact force due to the road of 48 kN; another contact force due to the road of 4.5 kN, directed east; and a drag force due to air resistance of 0.9 kN, directed west. What is the net force acting on the truck?
and in what direction is it moving?





3.Vector a has components ax = - 2.9 m/s2 and ay = + 4.1 m/s2.

(a) What is the magnitude of vector a?
____ m/s2

(b) What is the direction of vector a?
____ ° CCW from the +y-axis
 
Physics news on Phys.org
Well for 1) you know the guy is floating. In other words, he's not sinking or rising, so the net force on him in the vertical axis is 0. You know the force of gravity on him, it's given. You know the net force is 0. Sooo you know _______ <--take a stab

2)Draw it and use trig

3)Same as above. It's one vector with magnitude 2.9 m/s^2 going left on the x axis, and one going 4.1 m/s^2 up. You can draw a right triangle and use trig
 

Similar threads

Replies
10
Views
2K
  • · Replies 39 ·
2
Replies
39
Views
4K
  • · Replies 33 ·
2
Replies
33
Views
3K
Replies
8
Views
7K
Replies
3
Views
2K
Replies
39
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 21 ·
Replies
21
Views
10K