OK, so, now that I've broken down the circuit to what is pictured, can i break it down anymore? the last picture of the first attachment shows a circuit with 3 resistors, but i don't know at this point how to find the net resistance...
please help, thanks.
I think you went wrong at the first step. You made a resistor disappear that is NOT parallel to anything. It does not matter in what direction resistances are drawn.
If R1 and R2 are parellel, one side of R1 is connected to one side of R2, and the other side of R1 is connected to the other side of R2.
In the original circuit there are no resistances that are parallel (but there will be once you start replacing series resistances)
so, from the original circuit, do you agree that, when all combined, there are 2 resistors in parallel and one resistor that runs diagonal within the circuit?
so, from the original circuit, do you agree that, when all combined, there are 2 resistors in parallel and one resistor that runs diagonal within the circuit?
No. If you combine everything that can be combined, you will have only one resistor left.
i've attached what i got. please check it out. i have all my process written out, with each circuit breakdown and whether that part is parallel or series. please check it out and let me know if/where i went wrong. thank you.
Your last step to combine R2 and R4 is invalid. These are not parallel.
One side of R2 is connected to one side of R4, the other side of R2 is NOT connected to the other side of R4, so they are not parallel
There's a pair of series resistances in your next to last circuit.
You combined R2 and R6 which are not in series. Two resistors are in series if they are connected to each other AND if nothing else is connected to the wire that connects the resistors. This last condition isn't valid.
There are 2 parallel resistances you can combine at the point where you made that mistake.