What Is the Net Torque on a Uniform Beam?

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SUMMARY

The net torque on a 4.5-meter-long uniform beam can be calculated using the formula τ = F * θ, where τ represents torque, F is the force applied, and θ is the angle of application. The discussion highlights the calculation of torque about two points: the center of mass (point C) and one end (point P). The correct approach involves using the component of force perpendicular to the beam and the distance from the point of rotation. The final calculation for the uppermost force yields a torque of 56 * sin(30) * (4.5/2) Nm.

PREREQUISITES
  • Understanding of torque and its calculation using τ = F * θ
  • Knowledge of forces acting on beams and their components
  • Familiarity with trigonometric functions, specifically sine
  • Basic principles of static equilibrium in physics
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  • Explore the role of trigonometric functions in physics problems involving angles
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Students studying physics, particularly those focusing on mechanics, as well as educators and professionals involved in engineering and design who require a solid understanding of torque and beam dynamics.

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Homework Statement



Determine the net torque on the 4.5-m-long uniform beam shown in the figure:
http://session.masteringphysics.com/problemAsset/1057865/3/GIANCOLI.ch10.p030.jpg"

A) Calculate about point C, the center of mass (CM)

B)Calculate about point P at one end.

Homework Equations



[itex]\tau=F*\theta[/itex]

The Attempt at a Solution



In this case I have the answers for the values with the same figure, so I know the summation of forces along this pole must be equal to 8.5 N. From there I multiply the length of my bar to get 38 Nm, which is correct. However, I don't know how to get this from the figure. From there, I have no idea how to get the torque around point p.
 
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The formula is not correct. It should be the component of force perpendicular to the rod times the distance from the point.

For the uppermost force, it would be
Torque = 56*sin(30)*4.5/2
 

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