What Is the Optimal Angle for Maximum Range in Projectile Motion on a Slope?

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A boy stands at the peak of a hill which slopes downward uniformly at angle [tex]\phi[/tex]. At what angle [tex]\theta[/tex] from the horizontal should he throw a rock so that is has the greatest range.

Ok, so this is a rotation of the normal [tex]x_{1} - x_{2}[/tex] plane right? So we can use the direction cosines [tex]\lambda_{ij}[/tex] to make this problem easier.

So [tex]x'_{1} = x_{1} \cos \phi + x_{2} \cos \left(\frac{\pi}{2} + \phi \right)[/tex] and [tex]x'_{2} = \cos \theta + \cos \phi[/tex].

Are these the right transformations? Is this the right way to set up the problem? Then just apply the equations of projectile motion? This problem seems pretty difficult if I didn't have these tools available. But basically I am using the following:

[tex]A = \begin{bmatrix} \lambda_{11} & \lambda_{12} & \lambda_{13} \\ \lambda_{21} & \lambda_{22} & \lambda_{23} \\ \lambda_{31} & \lambda_{32} & \lambda_{33} \end{bmatrix}[/tex]
 
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At the risk of sounding like an uneducated fool:

Isn't 45° always the most effective angle to use?