What is the Optimal Throw Angle with Horizontal Wind Force?

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Homework Statement


What is the thrown angle of a body with a weight w, to make the maximun height equal to the horizontal lenght. Also exists a horizontal wind's force F that acts over the body?

The Attempt at a Solution


I think these are the relations, or i am wrong?
1. (Vo^2.sin^2[tex]\alpha[/tex])/2g = (Vo^2.sin[tex]\alpha[/tex])/g
2. Vox = Vox . Cos[tex]\alpha[/tex] - F
Voy = Voy sen[tex]\alpha[/tex] - W
 
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Equated range with max. height but range changes with the horizontal force. The other two relations I do not understand. Could you please tell us what you are thinking?
 
aim1732 said:
Equated range with max. height but range changes with the horizontal force. The other two relations I do not understand. Could you please tell us what you are thinking?

The other relations are just the initial velocity of the body in the x-axis and in the y axis. I am trying to use that relations to solve the problem, they are not part of the problem

The problem is to calculate the angle, and the conditions are: - the max height = horizontal length , also the wind force F acts over the body, also is considered the weight of the body.

I suposse that the wind force F changes the body velocity in the x-axis so there an desaceleration, and the body's weight w modifies the movement in the y axis, so what could the relations to solve that.
 
I think you need to stop guessing.
Apply the equations of motion along the horizontal and vertical directions separately. Calculate range and max. height and equate them. Trying to use the standard formulae for projectiles is confusing you.