What is the orbital period of an asteroid between Earth and Jupiter?

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SUMMARY

The orbital period of an asteroid located between the orbits of Earth and Jupiter can be determined using Kepler's third law. The correct formula for the orbital period T is T = 2π (a³/μ)^(1/2), where μ is the gravitational parameter defined as μ = GMs. The semi-major axis a should be the average of the radii of Earth's and Jupiter's orbits, specifically a = (LE + LJ)/2, rather than solely using Jupiter's orbital radius, which leads to an incorrect calculation of Jupiter's orbital period.

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TheBigDig
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Homework Statement


The orbit of an asteroid extends from the Earth’s orbit to Jupiter’s orbit, just touching both. Assume that the planetary orbits are circular and co-planar and that Newton’s constant G, the mass of the sun Ms, the mass of the asteroid ma and the radii of the Earth’s and Jupiter’s orbit respectively, (LE, LJ ), are known.
1. Find the orbital period of the asteroid.Express all of your answers in terms of the given quantities of the problem: G, Ms, ma,LE and LJ

Homework Equations


T = 2π (a3/μ)1/2 where T is the period, a is the semi-major axis of the orbit and μ is the gravitational mass of the sun (μ = GMs)

The Attempt at a Solution


I'm actually really stuck on this one though it seems simple. It seems like the answer is T = 2π (LJ3/μ)1/2 but I am almost certain that is wrong. It just seems to easy to me.
 
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TheBigDig said:
3. I'm actually really stuck on this one though it seems simple. It seems like the answer is T = 2π (LJ3/μ)1/2 but I am almost certain that is wrong. It just seems to easy to me.
That is because for a you used the orbital radius of Jupiter's orbit. What you found was the period of Jupiter's orbit. What you need here is the semi-major axis. Try a diagram.
 
Make a sketch of the orbit and identify the major axis.
 

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