What is the oscillation frequency of a vibrating hydrogen molecule?

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SUMMARY

The oscillation frequency of a vibrating hydrogen molecule (H2) can be calculated using the formula f = (1 / 2π) * √(k / m_eff), where k is the spring constant (500 N/m) and m_eff is the effective mass (0.5 * mass of a hydrogen atom). Given the mass of a hydrogen atom as 1.008 u (1 u = 1.661 × 10-27 kg), the correct calculation yields an oscillation frequency of approximately 1.23 × 1014 Hz. The initial miscalculation was due to incorrect placement of brackets in the formula, leading to an erroneous result of 1.22 × 1015 Hz.

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Homework Statement


When displaced from equilibrium by a small amount, the two hydrogen atoms in an H2molecule are acted on by a restoring force Fx=−k1x with k1 = 500N/m.

Calculate the oscillation frequency f of the H2 molecule. Use meff=m/2 as the "effective mass" of the system, where m is the mass of a hydrogen atom.
Take the mass of a hydrogen atom as 1.008 u, where 1u=1.661×10−27kg. Express your answer in hertz.

Homework Equations


f=\frac{ 1 }{ 2 pi } sqrt{\frac{ k }{ m_{eff} }}

The Attempt at a Solution


So plugging everything in I get f=\frac{ 1 }{ 2 pi } sqrt{\frac{ 2 times 500 }{ 1.661 times 10^{-27} }} giving me a final answer of 1.22*10^15 Hz, but the answer is 1.23*10^14 Hz, I have no idea what I did wrong?
 
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Your thinking is correct, your numerical result is wrong. The expression you give evaluates to 1.2e14 Hz.
 
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Oh wow, that was dumb of me, I didn't put the brackets around 2 pi, so it put pi in the numerator for me ha.

Thank you so much for confirming :)
 

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