What Is the Percent Yield from Aluminum to Potassium Alum?

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SUMMARY

The discussion centers on calculating the percent yield of potassium alum from aluminum, with a focus on the reaction involving 5.00 g of aluminum yielding 75.0 g of potassium alum. The theoretical yield calculated is 47.84882537 g, derived from the molar mass of aluminum (26.98156 g/mol) and potassium alum (258.207 g/mol). The discrepancy between the theoretical yield and the actual yield indicates a misunderstanding of the reaction equation and the composition of potassium alum, which is more complex than KAl(SO4)2. Participants emphasize the importance of correctly identifying the formula and significant figures in stoichiometric calculations.

PREREQUISITES
  • Understanding of stoichiometry and chemical reactions
  • Knowledge of molar mass calculations
  • Familiarity with significant figures in scientific calculations
  • Basic chemistry concepts related to aluminum and potassium alum
NEXT STEPS
  • Review the complete reaction equation for the formation of potassium alum from aluminum
  • Study the molar mass of potassium alum in detail to ensure accurate calculations
  • Learn about significant figures and their application in chemical calculations
  • Explore the properties and uses of potassium alum in various applications
USEFUL FOR

Chemistry students, educators, and anyone involved in chemical calculations or studying the properties of aluminum and potassium alum will benefit from this discussion.

Lili123
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Please post this type of questions in HW section using the template.
Here is the question: If 75.0 g of potassium alum is obtained from 5.00 g of aluminum, what is the percent yield?

This is what I've done so far, but I'm not sure if it is fully correct:
5.00g Al x (1/26.98156) x (1/1) x 258.207 = 47.84882537g potassium alum

Wouldn't this then be the theoretical yield? But then that wouldn't work because the actual yield of 75.0g is much greater... is there something I did wrong here?
 
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Lili123 said:
5.00g Al x (1/26.98156) x (1/1) x 258.207 = 47.84882537g potassium alum

And you expect us to guess what these numbers mean?

Please start by writing the reaction equation. What is the formula of the alum? Hint: it is not just KAl(SO4)2.
 
Another hint: You've been given a three significant figure problem. Piling on significant figures is neither useful nor impressive.
 
Last edited:

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