What is the pH of a Soft Drink with NaH2PO4 and Na2HPO4?

AI Thread Summary
To determine the pH of a soft drink containing NaH2PO4 and Na2HPO4, focus on the equilibrium between H2PO4(-) and HPO4(2-), as the concentrations of other species are negligible. The Henderson-Hasselbalch equation can be applied to calculate the pH, using the appropriate dissociation constant (Ka) for the relevant equilibrium. It is generally unnecessary to consider the first and third deprotonations of phosphoric acid, as they contribute minimally to the overall pH. Including all equilibria may complicate the calculation without significantly affecting the result. This approach provides a clear method for solving weak acid and weak base mixtures in buffer solutions.
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Hi

I have been trying several days to solve this problem. But i can't find the procedure to solve this weak acid and weak base problem. I will really appreciate some help.

What is the pH of a soft drink in which the major buffer ingredients are 6.90 g of NaH2PO4 and 5.70 g of Na2HPO4 per 355 mL of solution?

Thanks
 
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Hi

The problem relies in the fact i don't know how to solve for weak acid with a weak base. I do know how to buffers with weak acid and salt or weak base and salt. But I have no idea where to start when you are asked a mixture of weak acid and weak base at the same time. I will really appreciate your help. I don't need the final answer just a way to solve this kind of problem.

Thanks
 
I think that the conceptual key here is that you can largely ignore the first and third deprotonations of phosphoric acid. If H2PO4(-) and HPO4(2-) exist in significant concentration, then the concentrations of H3PO4 and PO4(3-) will be negligible. That is to say, the only significant equilibrium here is

H2PO4(-) <-> H(+) + HPO4(2-), all phases aqueous.

Then you can just apply the Henderson-Hasselbach equation. Just make sure you use the right Ka.

If you feel paranoid and want to include all of the other equilibria, you can. I'm guessing it'll just be extra work for a 10^-18 or so correction.
 
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