renerob Messages 20 Reaction score 0 Thread starter Mar 1, 2010 #1 If e=mc^2, then (e/m)1/2= either +c or -c. What is the physical meaning of minus c?
Matterwave Science Advisor Homework Helper Gold Member Messages 4,380 Reaction score 684 Mar 2, 2010 #2 e=mc^2 shouldn't be used to try to find "c". "c" is a defined constant of 299792458 m/s.
dreiter Messages 33 Reaction score 0 Mar 2, 2010 #3 Mathematically -c exists, but this is a non-physical result, and is therefore ignored when using the e=mc2 equation. :)
Mathematically -c exists, but this is a non-physical result, and is therefore ignored when using the e=mc2 equation. :)
Nabeshin Science Advisor Messages 2,207 Reaction score 16 Mar 2, 2010 #4 Matterwave said: e=mc^2 shouldn't be used to try to find "c". "c" is a defined constant of 299792458 m/s. Precisely. Imagine the equation like this: [tex]E=m(2)^2[/tex] [tex]2=\pm \sqrt{\frac{E}{m}}[/tex] Hope this clarifies.
Matterwave said: e=mc^2 shouldn't be used to try to find "c". "c" is a defined constant of 299792458 m/s. Precisely. Imagine the equation like this: [tex]E=m(2)^2[/tex] [tex]2=\pm \sqrt{\frac{E}{m}}[/tex] Hope this clarifies.