# What is the physical or statistical meaning of this integral

What is the physical or statistical meaning of the following integral

$$\int^{a}_{o} g(\vartheta) d(\vartheta)$$ = $$\int^{\infty}_{a} g(\vartheta) d(\vartheta)$$

where $$g(\vartheta)$$ is a Gaussian in $$\vartheta$$ describing the transition frequency fluctuation in a gaseous system (assume two-level and inhomogeneous) .

$$\vartheta = \omega_{0} -\omega$$, where $$\omega_{0}$$ is the peak frequency and $$\omega$$ the running frequency.

I can see that the integral finds a point $$\vartheta = a$$ for which the area under the curve (the Gaussian) between 0 to a and a to $$\infty$$ are equal.

But is there a statistical meaning to this integral? Does it find something like the most-probable value $$\vartheta = a$$? But the most probable value should be $$\vartheta = 0$$ in my understanding! So what does the point $$\vartheta = a$$ tell us?

I will be grateful if somebody can explain this and/or direct me to a reference.

Cheers

Jamy

tiny-tim
Homework Helper
$$\int^{a}_{o} g(\vartheta) d(\vartheta)$$ = $$\int^{\infty}_{a} g(\vartheta) d(\vartheta)$$

But is there a statistical meaning to this integral?

Hi Jamy! It's the 50% likelihood range …

50% likely that the result will be between ±a

(and it works for any symmetric probability distribution, not just Gaussian )

Hi Jamy! It's the 50% likelihood range …

50% likely that the result will be between ±a

(and it works for any symmetric probability distribution, not just Gaussian )

Thanks a ton for the reply. Could you please provide a reference/book. I want to see how its 50% likely.
Cheers
Jamy Well I suppose the domain is on positive values. For it to be a probability distribution its norm should be unity.

$$\int^{\infty}_{o} g(\vartheta) d(\vartheta) = 1$$

The 50% follows from 11th grade math, by the rules of how to add integrals over different intervals.