What is the polar form of the complex number 3-4i

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Homework Help Overview

The discussion revolves around finding the polar form of the complex number 3-4i, focusing on the definitions and interpretations of polar representation in complex numbers.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the polar form using the equation z=r*cos(theta)+i*r*sin(theta) and question the validity of a multiple-choice answer that evaluates cos and sin, potentially removing the angle theta.

Discussion Status

There is an ongoing exploration of what constitutes polar form, with some participants expressing confusion over the evaluation of trigonometric functions in the context of polar representation. The discussion includes differing opinions on the correctness of the provided answers and their presentation.

Contextual Notes

Participants note that the problem is part of a multiple-choice quiz, which may impose constraints on the expected format of the answer. There is also mention of a potential arithmetic mistake in one of the attempts.

willibre
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Homework Statement


What is the polar form of the complex number 3-4i?


Homework Equations



z=r*cos(theta)+i*r*sin(theta)

The Attempt at a Solution


5(cos(arctan(-4/3))-i*sin(arctan(-4/3)))

This is what I thought the correct answer would be, but it was a multiple choice quiz and this was not one of the options. The correct answer, according to the quiz, was 5(3/5-i*4/5). I don't see how that is in polar form, since the cos and sin of theta were both evaulated. If that is actually correct, then couldn't you simply make any standard complex number polar form by factoring out r?
 
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For the angle theta in question, the triangle is a 3-4-5 right triangle. cos(theta) = 3/5 and sin(theta) = -4/5.
 
willibre said:

Homework Statement


What is the polar form of the complex number 3-4i?


Homework Equations



z=r*cos(theta)+i*r*sin(theta)

The Attempt at a Solution


5(cos(arctan(-4/3))-i*sin(arctan(-4/3)))

This is what I thought the correct answer would be, but it was a multiple choice quiz and this was not one of the options. The correct answer, according to the quiz, was 5(3/5-i*4/5). I don't see how that is in polar form, since the cos and sin of theta were both evaulated. If that is actually correct, then couldn't you simply make any standard complex number polar form by factoring out r?

Except for the arithmetic mistake already pointed out, I agree with you. Some authors might call the polar form r\, cis(\theta) or re^{i\theta} which would make the argument even stronger that their "best" answer isn't appropriate.
 
I guess my question is, why is it still considered polar form if you carry out the evaluation of cos and sin, thus removing theta? Why wouldn't any polar form then just be r(a/r+ib/r). I guess I don't understand what is technically considered polar form.
 
willibre said:
I guess my question is, why is it still considered polar form if you carry out the evaluation of cos and sin, thus removing theta?

It isn't. The answers to that test question were incorrectly presented.
 

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