What is the pressure exerted on the bottom of a pool in the deep end?

  • Thread starter Thread starter mr.toronto
  • Start date Start date
AI Thread Summary
The pressure exerted on the bottom of a pool in the deep end, where the water is 3 meters deep, is calculated using the formula P = force/area. With a pool volume of 135 cubic meters, this equates to a weight of 135 tons. The area of the pool is 45 square meters, leading to a pressure of 3000 pascals. Conversions to other units, such as pounds per square inch, can be performed using the conversion factor of 1 pascal = 145.04×10^-6 psi. The final result confirms the pressure at the bottom of the pool.
mr.toronto
Messages
13
Reaction score
0

Homework Statement


What is the pressure exerted one the bottom of a pool in the deep end? The water is 3m deep and the dimensions are 7.5mx6m.


Homework Equations


volume of pool-3mx7.5mx6m=135mcubed

1m cubed= 1 ton 1000kg

135m cube= 135 tons


The Attempt at a Solution


3000p
 
Physics news on Phys.org
I know the answer is 3000 pascal can somebody help me show that
 
P = force/area = 135 tons/(6 x 7.5 m^2) = ? lbs/? in^2 = ? Pa

1 pascal = 145.04×10^-6 psi.

Just do the coversion.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top