What is the pressure exerted on the bottom of a pool in the deep end?

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SUMMARY

The pressure exerted on the bottom of a pool in the deep end, where the water depth is 3 meters, is calculated to be 3000 Pascals. This is derived from the formula P = F/A, where the force is the weight of the water (135 tons) and the area is the bottom surface area of the pool (45 m²). The conversion from Pascals to psi is also noted, with 1 Pascal equating to 145.04×10^-6 psi.

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Homework Statement


What is the pressure exerted one the bottom of a pool in the deep end? The water is 3m deep and the dimensions are 7.5mx6m.


Homework Equations


volume of pool-3mx7.5mx6m=135mcubed

1m cubed= 1 ton 1000kg

135m cube= 135 tons


The Attempt at a Solution


3000p
 
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I know the answer is 3000 pascal can somebody help me show that
 
P = force/area = 135 tons/(6 x 7.5 m^2) = ? lbs/? in^2 = ? Pa

1 pascal = 145.04×10^-6 psi.

Just do the coversion.
 

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