What Is the Probability That the Maximum of Two Drawn Balls Is 9?

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To find the probability that the maximum of two drawn balls is 9, we consider the possible outcomes when drawing balls numbered 1 to 10 with replacement. The maximum value Z can be 9 if at least one of the balls drawn is 9, while the other can be any number from 1 to 9. There are 17 favorable outcomes where Z equals 9, and the total number of outcomes when drawing two balls is 100. Thus, the probability P(Z=9) is calculated as 17 out of 100, or 0.17. This indicates that there is a 17% chance that the maximum of the two drawn balls will be 9.
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we have numbered balls in a bag from 1 to 10. We put our hand and take one. Let the number of X be the first number of the ball. Replace the ball into the bag again and takes another ball at random. Let the number of Y the number of the second ball.

IF Z =max{X, Y}.

we want to find P(Z=9)


First of all i used the type (n+k-1)c(k) because we replace the ball again and i found this (8)c(55) but its says tha its not correct answer, what i am doing wrong?
 
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There are 17 possible ways you choose 2 balls with replacement such that Z=max(X,Y)=9. The number of all possible ways you choose 2 balls with replacement is 100. Now you should be able to find the answer.
 
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