What Is the Probability That the Maximum of Two Drawn Balls Is 9?

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SUMMARY

The discussion focuses on calculating the probability that the maximum of two drawn balls, labeled from 1 to 10, equals 9. The correct approach involves recognizing that there are 17 favorable outcomes where the maximum value Z equals 9, out of a total of 100 possible outcomes when drawing with replacement. The probability P(Z=9) is therefore calculated as 17/100, which simplifies to 0.17 or 17%. The initial use of the combination formula (n+k-1)c(k) was incorrect for this scenario.

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we have numbered balls in a bag from 1 to 10. We put our hand and take one. Let the number of X be the first number of the ball. Replace the ball into the bag again and takes another ball at random. Let the number of Y the number of the second ball.

IF Z =max{X, Y}.

we want to find P(Z=9)


First of all i used the type (n+k-1)c(k) because we replace the ball again and i found this (8)c(55) but its says tha its not correct answer, what i am doing wrong?
 
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There are 17 possible ways you choose 2 balls with replacement such that Z=max(X,Y)=9. The number of all possible ways you choose 2 balls with replacement is 100. Now you should be able to find the answer.
 
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