What is the Proper Subspace Hierarchy in a Vector Space with Infinite Subsets?

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The discussion centers on proving that the union of an infinite collection of proper subspaces, {W_1, W_2, W_3,...}, is also a proper subspace of a vector space V. The participant has established that the union U(W_i) is a subspace but struggles to demonstrate that it is not equal to V. They explore the implications of using induction and the axiom of choice, questioning the validity of defining V as the union of the W's. A counterexample is presented using the vector space of polynomials, where the union of subspaces of polynomials of increasing degree equals V, challenging the original assertion. The conversation highlights the complexities of infinite set theory in the context of vector spaces.
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Homework Statement


Let {W_1,W_2,W_3,...} be a collection of proper subspaces of V (i.e. W_i not=V) such that W_i is a subset of W_(i+1) for all i. Prove that U(W_i) (i from 1 to infinity) is a proper subspace of V

The Attempt at a Solution


I've already proven that U(W_i) is a subspace of V, so I only need to show that U(W_i) not= V. I've used induction but that only proves that W_i (i from 1 to n) is a proper subset of V, not U(W_i) (i from 1 to infinity). How do I show that U(W_i) (i from 1 to infinity) is a proper subset of V? I'm familiar with infinite set theory stuff (axiom of choice, etc...), but I don't know how to use it here. I could not use dimensions to help me because infinity minus a number is still infinity. Should I use the complement subsets of W_i?
 
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Why can't you DEFINE V to be the union of the W's. Doesn't that V meet all of your premises? But the union of the W's now IS V. I don't see how you could prove the union is a proper subspace.
 
V is given. I cannot give it any definition. {W_1,W_2,W_3,...} is defined to be a collection of proper subspaces of V. I can define Y to be the union of the W's, but then I have to show that Y is a proper subset of V.
 
I'm pointing out that Y is a counterexample to what you are trying to prove. So what you are trying to prove can't be true for all V.
 
Or maybe there is something you haven't told us about V. Does it have some sort of completeness property?
 
For a specific counterexample, let V be the vector space of all polynomials. For every n, let Wn be the subspace of all polynomials of degree less than or equal to n. I believe that satisfies the conditions. The union of all such spaces is V itself.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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