What is the rate of heat conduction through a 30 m thickness of rhyolite lava?

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Homework Help Overview

The problem involves calculating the rate of heat conduction through a 30 m thickness of rhyolite lava, given specific temperatures on either side and the thermal conductivity of the material.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of the temperature gradient and question the multiplication by thickness instead of division. There is also a mention of needing an area value for the calculation.

Discussion Status

The discussion includes clarifications on the formula used and the correct interpretation of the temperature gradient. Some participants are exploring different interpretations of the calculations, and there is a moment of realization from one participant.

Contextual Notes

There is an assumption regarding the area for the calculation, which remains unspecified in the discussion.

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Homework Statement



A lava beds cool very slowly, remaining warm for years. Calculate the rate of heat conduction per square metre through a 30 m thickness of rhyolite, if the surface is 400 degrees celsius and its interior side is at 3100 degrees celsius. The thermal conductivity of rhyolite =0.84 Wm^-1 degrees celsius^-1.

Answer must be 75.6 W/m^2


Homework Equations



[tex]P=kA \left| \frac{dT}{dx}\right|[/tex]

(The rate is P, k is thermal conductivity, dT/dx is temprature gradient)

The Attempt at a Solution



dT/dx = 3100-400 = 2700

[tex]0.84 \times 30 \times(2700) = 68040[/tex]

Can anyone show me the problem? ...because the right answer is 75.6!
 
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Why are you multiplying by 30 instead of dividing? dT/dx is 2700/30.
 
ideasrule said:
Why are you multiplying by 30 instead of dividing? dT/dx is 2700/30.

Yes, but I need a number for area A!
 
Oh, never mind I get it. THANKS!
 

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