What is the relationship between the perpendiculars in a 3D vector?

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SUMMARY

The discussion focuses on the relationship between perpendiculars in a 3D vector context, specifically involving points P and Q in relation to a base defined by points A, B, C, and D. The k component is established as 5, while the j component is determined to be 4j, derived from the midpoint of DE, which is positioned over the intersection of diagonals OB and AC. The i component is calculated as 4, resulting from the difference between the lengths of OA (14) and DE (6), split evenly between the two sides.

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lionely
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Homework Statement



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I'm confused ,here's ... my attempt..

all I know so far is the

the k component would be 5...
I have no idea what to do with the i and j
 
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hi lionely! :smile:
lionely said:
all I know so far is the

the k component would be 5...
I have no idea what to do with the i and j

drop perpendiculars DP and EQ onto the base …

where are P and Q in relation to ABCD ? :wink:​
 
Hint: Assume DE is located such that its midpoint is positioned directly over the intersection of the base diagonals OB and AC.
 
Hmm is DE is assumed to be at the mid point then.. for the j component that would be 4j

but the i? ... umm is it like the base below DE is 8 because DE is 6cm and OA is 14? so 14-6?
 
tiny-tim said:
hi lionely! :smile:


drop perpendiculars DP and EQ onto the base …

where are P and Q in relation to ABCD ? :wink:​

when I dropped the perpendiculars they ended up being at the midpoints of the widths of the base
 
lionely said:
Hmm is DE is assumed to be at the mid point then.. for the j component that would be 4j

but the i? ... umm is it like the base below DE is 8 because DE is 6cm and OA is 14? so 14-6?

You had your answer in this post, but didn't realize it. 14 - 6 = 8, and this difference is split evenly between between the two sides. So the i component is 4.
 
hi lionely! :smile:

(just got up :zzz:)
lionely said:
when I dropped the perpendiculars they ended up being at the midpoints of the widths of the base

(we'll call them P and Q)

ok … so the next line in your proof would be to say what the distance PQ is

and then you can compare that with the length of the base :wink:
 

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