- #1
Taylor_1989
- 402
- 14
Homework Statement
Find the general solution to the equation: ##{u}\times{(i+4j)}=3k##
Homework Equations
##u=(ai+bj+ck)##
The Attempt at a Solution
I am having trouble visualising what to do here.
So my throught so far is that, if i do ##(ai+bj+ck)\times {(i+4j)}=(0i-0j+(4a-b)k) ##
now if I equate ##(0i-0j+(4a-b)k)=(0i+0j+3k)## I get ##4a-b=3## and this is where i draw a blank,it's the general equation part that I don't get.
I mean if I rearange I could do for a or b, I preffer b as it have no fractions, ##4a-3=b##, so I assume that I would sub this back into u which would give me ##u=(0i+(4a-3)j+0k)##. Now doe the general equation, mean vector equation of the line. Normally I would find the direction vector and the starting vector but it being a cross product has thrown me a bit. Am I on the right lines or have I gone very wrong?