What is the relationship between the perpendiculars in a 3D vector?

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Homework Help Overview

The discussion revolves around understanding the relationship between perpendiculars in a 3D vector context, specifically focusing on components in a vector and their geometric interpretations related to a base structure.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants express confusion regarding the i and j components of a vector, with attempts to relate them to geometric positions and dimensions. There are discussions about dropping perpendiculars onto a base and the implications of their midpoints.

Discussion Status

Some participants have offered hints and guidance regarding the placement of points and the calculation of vector components, while others are exploring different interpretations of the geometric setup. The conversation reflects a mix of attempts to clarify the problem and to understand the relationships between the components.

Contextual Notes

There are references to specific dimensions and relationships within the problem, including the lengths of segments and the positioning of points, which may be critical for resolving the confusion but are not fully articulated.

lionely
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Homework Statement



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I'm confused ,here's ... my attempt..

all I know so far is the

the k component would be 5...
I have no idea what to do with the i and j
 
Last edited:
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hi lionely! :smile:
lionely said:
all I know so far is the

the k component would be 5...
I have no idea what to do with the i and j

drop perpendiculars DP and EQ onto the base …

where are P and Q in relation to ABCD ? :wink:​
 
Hint: Assume DE is located such that its midpoint is positioned directly over the intersection of the base diagonals OB and AC.
 
Hmm is DE is assumed to be at the mid point then.. for the j component that would be 4j

but the i? ... umm is it like the base below DE is 8 because DE is 6cm and OA is 14? so 14-6?
 
tiny-tim said:
hi lionely! :smile:


drop perpendiculars DP and EQ onto the base …

where are P and Q in relation to ABCD ? :wink:​

when I dropped the perpendiculars they ended up being at the midpoints of the widths of the base
 
lionely said:
Hmm is DE is assumed to be at the mid point then.. for the j component that would be 4j

but the i? ... umm is it like the base below DE is 8 because DE is 6cm and OA is 14? so 14-6?

You had your answer in this post, but didn't realize it. 14 - 6 = 8, and this difference is split evenly between between the two sides. So the i component is 4.
 
hi lionely! :smile:

(just got up :zzz:)
lionely said:
when I dropped the perpendiculars they ended up being at the midpoints of the widths of the base

(we'll call them P and Q)

ok … so the next line in your proof would be to say what the distance PQ is

and then you can compare that with the length of the base :wink:
 

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