What is the relationship between torque and angular momentum in a rigid body?

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SUMMARY

The relationship between torque and angular momentum in a rigid body is defined by the equation Torque(ext) = dL/dt, where L represents angular momentum. For a stationary point S, angular momentum is calculated as L(s, cm) = Ʃ(ρi x mivi), and the external torque is given by dL(cm)/dt = Ʃτ(ext, CM). When considering an accelerating point P, the equation modifies to include additional terms related to the center of mass, specifically Ʃτ(ext, p) = dL(rel_p)/dt + ρ(cm) x Ma(p), illustrating the dependency of torque on both the angular momentum and the acceleration of the center of mass.

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naestibill
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Considering a Rigid Body/Angular Momentum/Torque

We know that Torque(ext) = dL/dt

Now with respect to stationary point S:
L(s, cm) = Ʃ(ρi x mivi)
and that dL(cm)/dt = Ʃτ(ext, CM)

Now with respect to ANY point, P, that is accelerating:
L(s,p) = L(cm) + ρ(cm) x Mv(cm)
And hence,
Ʃτ(ext, p) = dL(rel_p)/dt + ρ(cm) x Ma(p)
Ʃτ(ext, p) = dL(rel_cm)/dt + ρ(cm) x Ma(cm)

Can someone explain to me why this happens?:
Why this happens? : Ʃτ(ext, p) = dL(rel_p)/dt + ρ(cm) x Ma(p)

Thanks
 
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