What is the Required Centripetal Acceleration for a Stone to Reach 25 Meters?

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SUMMARY

The required centripetal acceleration for a stone to reach a distance of 25 meters when thrown from a sling of length 1.3 meters and a release height of 2.7 meters can be calculated using the formula for centripetal acceleration, ac = v^2/r. To determine the necessary velocity, one must first calculate the time the stone is in the air, which is influenced by the height from which it is released. The discussion emphasizes the importance of understanding projectile motion and the relationship between velocity, time, and distance.

PREREQUISITES
  • Understanding of centripetal acceleration and its formula, ac = v^2/r
  • Knowledge of projectile motion principles
  • Familiarity with basic kinematic equations
  • Ability to calculate time of flight for a projectile
NEXT STEPS
  • Calculate the time of flight for a stone released from a height of 2.7 meters
  • Determine the initial velocity required to achieve a horizontal distance of 25 meters
  • Explore the effects of varying sling lengths on required centripetal acceleration
  • Investigate the relationship between release angle and distance in projectile motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and projectile motion, as well as educators looking for practical examples of centripetal acceleration applications.

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Homework Statement



You plan to throw stones by using a sling of length 1.3 m which you whirl over your head. Suppose you wish to throw a stone a distance of 25 m. What must be the centripetal acceleration of the stone just before its release if it is to reach this distance? Assume that the release height is 2.7 m.

Homework Equations



ac = v^2/r = (w^2)r = (4((pi)^2)r)/(T^2)

The Attempt at a Solution



I really don't know how to start this problem
 
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First figure out how fast you have to throw the stone to reach that distance. Hint: Assuming the stone is released horizontally, how long is it in the air?
 

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